Maths riddles are the ones where the trick is arithmetic rather than vocabulary. Some are genuine number puzzles that need working out; others look like arithmetic and turn on a piece of wordplay hidden in the question.

Every riddle here has its answer and, where the answer needs it, the working. That matters more in this category than any other - "the answer is 5" is useless if you cannot see why.

These are a good fit for maths lessons: they get pupils reasoning about number relationships without it looking like a worksheet.

1.HardMath Riddle

There are 500 coffins and 500 men who need them. The undertaker asks the first man to go to every coffin and open them. Then he tells the second man to go to every one and close it. The third one goes to every third coffin and so on. How many are open?

  • A.500
  • B.250
  • C.1
  • D.22
Answer: 22

Only coffins with an odd number of divisors stay open in the end - the perfect squares - and there are exactly 22 perfect squares (1 squared through 22 squared) at or below 500.

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2.HardMath Riddle

How do you go from 98 to 720 using just one letter?

  • A.Add a "7" in front of 98
  • B.Multiply 98 by itself
  • C.Add an "s" to make it plural
  • D.Add an "x" between "ninety" and "eight": Ninety x Eight = 720
Answer: Add an "x" between "ninety" and "eight": Ninety x Eight = 720

Spelling out "98" as "ninety eight" and inserting the letter x between the words creates "ninety x eight," which multiplies to 720.

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7.HardMath Riddle

In a bicycle race, the man who came two places in front of the last man finished one ahead of the man who came fifth. How many contestants were there?

  • A.5 contestants
  • B.7 contestants
  • C.8 contestants
  • D.There were 6 contestants. The man came in 4th place.
Answer: There were 6 contestants. The man came in 4th place.

If he's two places ahead of last (6th) he's in 4th, and finishing one ahead of 5th place also places him in 4th -- both conditions align only when there are 6 total contestants.

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8.HardMath Riddle

My daughter has many sisters. She has as many sisters as she has brothers. Each of her brothers has twice as many sisters as brothers. How many sons and daughters do I have?

  • A.Three daughters and four sons
  • B.Four daughters and four sons
  • C.Three daughters and three sons
  • D.Four daughters and three sons. Each daughter has 3 sisters and 3 brothers, and each brother has 2 brothers and 4 sisters.
Answer: Four daughters and three sons. Each daughter has 3 sisters and 3 brothers, and each brother has 2 brothers and 4 sisters.

With 4 daughters and 3 sons, each daughter has 3 sisters and 3 brothers (equal), and each son has 2 brothers and 4 sisters (twice as many sisters as brothers) -- satisfying both conditions.

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11.HardMath Riddle

There are 25 red balls, 47 green balls and 3 blue balls in a basket. There is a blind man. What is the minimum number of balls that the blind man has to pick to make sure that there are at least 2 balls of different colors?

  • A.3 balls
  • B.26 balls
  • C.4 balls
  • D.48 balls. There is a small chance he may pick up 47 green balls in a row.
Answer: 48 balls. There is a small chance he may pick up 47 green balls in a row.

In the worst possible case, the blind man could draw all 47 green balls in a row before finally getting a red or blue one, so 48 draws guarantee at least two different colors.

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16.HardMath Riddle

The combined age of Jack and John is 49. Jack is twice as old, as John was when Jack was as old as John is now. How old are the brothers?

  • A.Jack is 30 and John is 19
  • B.Jack is 25 and John is 24
  • C.Jack is 35 and John is 14
  • D.Jack is 28 and John is 21.
Answer: Jack is 28 and John is 21.

Jack's age (28) is twice what John's age was seven years ago (14), which is exactly the gap between their ages now (28 - 21 = 7), and 28 + 21 = 49 as required.

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17.MediumMath Riddle

How many days are there in 4 years?

  • A.1460
  • B.1462
  • C.1464
  • D.1461. (365 x 4) + 1, because one of the years is a leap year.
Answer: 1461. (365 x 4) + 1, because one of the years is a leap year.

Four years of 365 days would total 1,460 days, but one of the four is a leap year with an extra day, bringing the true total to 1,461.

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19.MediumMath Riddle

If you toss a coin 10 times and it lands heads up every time, what are the chances it will land heads up if you toss it again?

  • A.Very high, near 100%
  • B.Very low, near 0%
  • C.Exactly 90%
  • D.There is a 50/50 chance of each toss being either heads or tails. The previous toss does not impact the next toss.
Answer: There is a 50/50 chance of each toss being either heads or tails. The previous toss does not impact the next toss.

A fair coin has no memory -- each flip is an independent event with exactly a 50% chance of heads, regardless of past results.

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20.MediumMath Riddle

In a lake, there is a patch of lily pads. Every day, the patch doubles in size. If it takes 48 days for the patch to cover the entire lake, how long would it take for the patch to cover half the lake?

  • A.24 days
  • B.36 days
  • C.47.5 days
  • D.The patch doubles in size every day, so on the 47th day the patch will be half the size it is on the 48th day.
Answer: The patch doubles in size every day, so on the 47th day the patch will be half the size it is on the 48th day.

Since the patch's size doubles every single day, it must have covered exactly half the lake just one day before it covered the whole lake - day 47.

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21.HardMath Riddle

Dean Sam and Castiel are three brothers. Interestingly their current age is prime. What's more interesting that difference between their ages is also prime. How old are they?

  • A.2, 3, and 5
  • B.3, 5, and 7
  • C.2, 5, and 11
  • D.Sam is 2, Dean is 5, and Castiel is 7. The age differences (5-2=3, 7-5=2, 7-2=5) are all prime numbers.
Answer: Sam is 2, Dean is 5, and Castiel is 7. The age differences (5-2=3, 7-5=2, 7-2=5) are all prime numbers.

Ages 2, 5, and 7 are all prime numbers, and the differences between them - 3, 2, and 5 - are also all prime, satisfying every condition in the riddle.

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22.MediumMath Riddle

There are two fathers and two sons. They walk into a candy store and each buys a candy bar for 50 cents. The total for all of the candy bars was $1.50. How is that possible?

  • A.One father bought two bars
  • B.They got a discount
  • C.One son didn't buy one
  • D.There was a grandfather, a father and a son.
Answer: There was a grandfather, a father and a son.

With a grandfather, father, and son, the middle person counts as both a father and a son, giving 'two fathers and two sons' among only three people who buy just three candy bars.

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24.HardMath Riddle

How can you give someone $83 using exactly 7 bills, without using any one dollar bills?

  • A.1 fifty, 2 twenties, 5 ones
  • B.8 ten dollar bills and change
  • C.1 hundred bill and change back
  • D.Give them 1 fifty dollar bill, 1 twenty dollar bill, 1 five dollar bill and 4 two dollar bills.
Answer: Give them 1 fifty dollar bill, 1 twenty dollar bill, 1 five dollar bill and 4 two dollar bills.

A $50 bill, a $20 bill, a $5 bill, and four $2 bills together total $83 using exactly seven bills and no $1 bills.

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29.HardMath Riddle

A bat and a ball cost $1.10. The bat costs one dollar more than the ball. How much does the ball cost?

  • A.10 cents
  • B.15 cents
  • C.1 cent
  • D.The ball costs 5 cents, not 10 cents. One dollar more than 10 cents is $1.10, but $1.10 + 10 cents would be $1.20. One dollar more than 5 cents is $1.05, and the sum of that is $1.10.
Answer: The ball costs 5 cents, not 10 cents. One dollar more than 10 cents is $1.10, but $1.10 + 10 cents would be $1.20. One dollar more than 5 cents is $1.05, and the sum of that is $1.10.

If the ball costs 5 cents, the bat costs $1.05 (one dollar more), and together they total $1.10 -- the common wrong intuitive answer of 10 cents doesn't satisfy the 'one dollar more' condition.

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35.HardMath and Logic

Surprise test impossible logic?

  • A.The students are lazy
  • B.The professor lied
  • C.The test was on Monday
  • D.Paradox
Answer: Paradox

If the test hasn't happened by Thursday, the students know it must be Friday (so it's not a surprise). This logic continues backward to Monday, 'proving' it can never be a surprise.

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36.HardMath and Logic

Sphere or Torus using rocks?

  • A.Throw a rock and see if it hits
  • B.Measure the shadow
  • C.Taste the surface
  • D.Perpendicular loops
Answer: Perpendicular loops

On a sphere, any two 'great circles' must intersect. On a torus, you can have a loop that goes around the center and another through the hole that never meet.

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39.HardMath and Logic

Hourglass weigh more falling or at rest?

  • A.Less
  • B.Same
  • C.It varies randomly
  • D.More while falling
Answer: More while falling

When sand is in the air, its weight isn't recorded by the scale. However, the force of the sand hitting the bottom is greater than its static weight, resulting in a net increase during the flow.

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50.MediumMath and Logic

Reverses left/right but not up/down?

  • A.It reverses up/down too
  • B.It's an optical illusion
  • C.Your eyes are curved
  • D.Inverts Z-axis
Answer: Inverts Z-axis

If you point your finger to the right, the mirror image points to the right. The reversal is actually in the 'depth' (front to back) dimension relative to the mirror's surface.

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51.HardMath and Logic

Camel 3000 bananas, 1k km. Max reach?

  • A.1,000 bananas
  • B.0 bananas
  • C.1,500 bananas
  • D.533.3 bananas
Answer: 533.3 bananas

The camel must leave 'caches' of bananas. To minimize the 'cost' of travel, he moves the bananas in stages until the total supply matches his max capacity for the remaining distance.

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52.MediumMath and Logic

Get fair toss from biased coin.

  • A.Toss it once
  • B.Toss it three times
  • C.You can't
  • D.Toss twice
Answer: Toss twice

If you toss twice, the probabilities of HT and TH are both (p * (1-p)). Since these are equal, assigning one to 'Heads' and the other to 'Tails' creates a fair 50/50 result.

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85.MediumMath and Logic

Measure 4L using 3L and 5L jugs.

  • A.Fill 5 and pour into 3
  • B.Drink 1 liter
  • C.Estimate half a jug
  • D.Fill/pour sequence
Answer: Fill/pour sequence

Fill 3, pour into 5. Fill 3 again, pour into 5 until full. 1L remains in the 3L jug. Empty 5, put that 1L in. Fill 3 and add to the 5L jug to get 4L.

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94.EasyMath and Logic

How do you move Mount Fuji?

  • A.Use a crane
  • B.Blow it up
  • C.You can't
  • D.Creative answers
Answer: Creative answers

This tests lateral thinking. You can 'move' it by moving yourself relative to it, or by waiting for continental drift over millions of years.

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Frequently asked questions

No. Almost all of them need only arithmetic and careful reading. The difficulty is in spotting the structure, not in the calculation.

Yes - they are widely used as lesson starters. The explanations are written so a pupil can follow the reasoning after the fact.

Because many of them are really language puzzles wearing a number costume. Read the question twice before you start calculating.